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Q. If one million atoms of silver weigh $1.79 \times 10^{-16}g$, the gram atomic weight of silver is

Some Basic Concepts of Chemistry

Solution:

$1$ million $= 10^6$
Thus $10^6$ atoms weigh $1.79 \times 10^{-16}g$,
So $6.02 \times 10^{23}$ atoms weigh
$= \frac{1.79\,\times\,10^{-16}}{10^{6}} \times 6.023\times10^{23}\,g$