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  4. If one atom of an element A weighs 6.644 × 10-23 g, then number of gram-atoms in 20 kg of it is

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Q. If one atom of an element $A$ weighs $6.644 \times 10^{-23} g$, then number of gram-atoms in $20\, kg$ of it is

Some Basic Concepts of Chemistry

Solution:

Atomic weight of $A$

= weight of one atom $\times$ Avogadro's constant

$=6.644 \times 10^{-23} \times 6.023 \times 10^{23}=40\, g$

Number of gram-atoms (moles) in $20\, kg$

$=\frac{\text { weight in } g }{\text { atomic weight }}=\frac{20 \times 1000}{40}=500$