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Q. If on the $x$-axis electric potential decreases uniformly from $60\, V$ to $20\, V$ between $x =-2 \, m$ to $x =+2\, m$, then the magnitude of electric field at the origin

Electrostatic Potential and Capacitance

Solution:

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$E_{x}=\frac{40}{4}=10 \frac{ V }{ m }$
$E_{y} \neq 0$
$E=\sqrt{E_{x}^{2}+E_{y}^{2}}>10$