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  4. If Newton is redefined as the force of attraction between two masses (each of 1 Kg ) 1 meter apart, the value of G is :

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Q. If Newton is redefined as the force of attraction between two masses (each of $1 \,Kg$ ) $1$ meter apart, the value of $G$ is :

Laws of Motion

Solution:

$ F =\frac{G m_{1} m_{2}}{r^{2}} $
$ 1 \,N =\frac{G(1 kg )(1 kg )}{1 m^{2}} $
$G =1\, Nm ^{2} \,kg ^{-2}$