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Mathematics
If n is a non-negative integer and A = [1&0 1&1] , then An =
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Q. If $n$ is a non-negative integer and $A = \begin{bmatrix}1&0\\ 1&1\end{bmatrix} $ , then $A^n = $
COMEDK
COMEDK 2008
Matrices
A
$\begin{bmatrix}1&0\\ n - 1&1\end{bmatrix} $
11%
B
$\begin{bmatrix}1&0\\1&1\end{bmatrix} $
18%
C
$\begin{bmatrix}1&0\\n &1\end{bmatrix} $
65%
D
$\begin{bmatrix}1&n\\0&1\end{bmatrix} $
6%
Solution:
$A = \begin{bmatrix}1&0\\ 1&1\end{bmatrix}$
$ A^{2} = \begin{bmatrix}1&0\\ 1&1\end{bmatrix}\begin{bmatrix}1&0\\ 1&1\end{bmatrix} =\begin{bmatrix}1&0\\ 2&1\end{bmatrix} $
Similarly, $A^{3} =\begin{bmatrix}1&0\\ 3&1\end{bmatrix} $
$A^{4} = \begin{bmatrix}1&0\\ 4&1\end{bmatrix}$ and so on
Hence , $A^{n}= \begin{bmatrix}1&0\\ n&1\end{bmatrix} $