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Q. If $n_{e}$ and $n_{h}$ represent the number of free electrons and holes respectively in a semiconducting material, then for $n-$type semiconducting material

J & K CETJ & K CET 2008Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

In an $n$-type semiconductor, majority charge carriers are electrons and minority charge carriers are holes.
Therefore, $n_{e} >> n_{H}$