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Q. If $ Na^{+} $ on is larger than $ Mg^{2+} $ ion and $ S^{2-} $ ion is larger than $ Cl^{-} $ ion, which of the following will be stable soluble in water?

AMUAMU 2008

Solution:

Magnesium sulphide. Higher the lattice energy lower the solubility. Out of the four combinations possible, the lattice energy of $MgS$ (bi-bivalent ionic solid) is higher than those of $ Na_{2}S,\,MgCl_{2} $ (uni-bivalent or bi univalent ionic solids) and $NaCI$ uni-univalent ionic solids) and hence, $MgS$ is the leas soluble.