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Q. If $N_A$ is Avogadro's number, then the number of oxygen atom in one g-equivalent of oxygen is

Some Basic Concepts of Chemistry

Solution:

$G.M.M.$ of $O_{2}=32\,g$
Eq. mass $=\frac{\text{At . mass of O}}{\text{valency}}=\frac{16}{2}=8$
$32 \,g$ of oxygen contain oxygen atoms $= 2 \times N_{A}$
$\therefore 8\,g$ of oxygen contains oxygen atom
$=\frac{2\times N_{A}}{4}=N_{A}/ 2$