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  4. If n(A)= 8 and n(A∩ B)=2, then n(A∩ B)' ∩ A ) is equal to

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Q. If $n(A)= 8$ and $n\left(A\cap B\right)=2$, then $n\left(A\cap B\right)' \cap A ) $ is equal to

KEAMKEAM 2011Sets

Solution:

Given, $n(A)=8, n(A \cap B)=2$
$n\left((A \cap B)^{\prime} \cap A\right)=n(A)-n(A \cap B)$
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$n(A \cap B)=2$
$=8-2=6$