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  4. If n(A) = 12, n(B) = 8, n(A ∩ B) = 4, then n(A ∪ B) is equal to

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Q. If $n(A) = 12$, $n(B) = 8$, $n(A \cap B) = 4$, then $n(A \cup B)$ is equal to

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Solution:

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$
$= 12 + 8 - 4 = 16$.