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Chemistry
If N0 represents Avogadro's number, the number of valence electrons in 4.2 g of nitride ion ( N 3-) is
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Q. If $N_{0}$ represents Avogadro's number, the number of valence electrons in $4.2 \,g$ of nitride ion $\left( N ^{3-}\right)$ is
BHU
BHU 2009
A
$2.4 \,N_{0}$
B
$4.2\, N_{0}$
C
$1.6 \,N_{0}$
D
$3.2 \,N_{0}$
Solution:
Number of valence electrons $=\frac{4.2}{14} \times N_{0} \times 8$
$[\because$ Number of valence electrons $=5+3=8]$
$=2.4 \,N_{0}$