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Q. If muonic hydrogen atom is an atom in which a negatively charged muon ($\mu$) of mass about $207 m_e$ revolves around a proton, then first Bohr radius of this atom is $(r_e = 0.53 \times 10^{-10} m)$

Atoms

Solution:

According to Bohr’s atomic model,
$r\propto \frac{1}{m}$
$\Rightarrow \frac{r_{\mu}}{r_{e}} = \frac{m_{e}}{m_{\mu}}\quad...\left(i\right) $
Here, $r_{e} = 0.53 \times10^{-10} m ;$
$ m_{\mu} = 207 m_{e}$
$\therefore r_{\mu} = \frac{m_{e}}{207 m_{e}} \times0.53 \times10^{-10} $ (using $(i)$)
$ = 2.56\times10^{-13}m $