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Q. If $\mu_0$ is permeability of free space and $\epsilon_0$ is permittivity of free space, the speed of light in vacuum is given by

KCETKCET 2008Wave Optics

Solution:

The speed of light in vacuum is given by $\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}$.
where $\mu_{0}$ is permeability and $\varepsilon_{0}$ is permittivity of free space.