Thank you for reporting, we will resolve it shortly
Q.
If momentum is increased by 20%, then kinetic energy increases by
Physical World, Units and Measurements
Solution:
The kinetic energy is given by KE = $ \frac{ p^2 }{ 2 m } $
So, $ \triangle KE = \frac{ 2 p \triangle p }{ 2 m } = \frac{ p \triangle p }{ m } $
$ \Rightarrow \frac{ 4 KE }{ KE } = \frac{ 2 \triangle p }{ p } $
Thus, the final momentum becomes 1.2 p
So, percentage change in KE = $ \frac{ final \, KE - initial \, KE }{ initial \, KE } \times 100 $
= $ \frac{ 1.44 ( p^2 / 2 m ) - ( p^2 / 2 m ) }{ ( p^2 / 2 m ) } $ = 44%