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  4. If molecular weight of KMnO4 is M, then its equivalent weight in acidic medium would be

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Q. If molecular weight of $ KMn{{O}_{4}} $ is $M$, then its equivalent weight in acidic medium would be

WBJEEWBJEE 2007Some Basic Concepts of Chemistry

Solution:

$ MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{2+}}4{{H}_{2}}O $
Gain electrons $= 5$
Molecular weight $= M$
Equivalent weight $=\frac{\text{molecular weight}}{\text{gain electron}}$
$=\frac{M}{5} $