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Q. If ' $m$ ' is the mean of a Poisson distribution, then $P (x >0)$ $=$

TS EAMCET 2021

Solution:

Mean of poisson distribution $=m$
Then, $P(X=x)=\frac{e^{-m} m^x}{x !}, x=0,1,2,3, \ldots$
$ P(X>0)=1-P(X=0) $
$ =1-\frac{e^{-m_m 0}}{0 !}=1-e^{-m}$
$ =\frac{e^m-1}{e^{i n}}$