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  4. If ( log a/y-z)=( log b/z-x)=( log c/x-y), then a b c=

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Q. If $\frac{\log a}{y-z}=\frac{\log b}{z-x}=\frac{\log c}{x-y}$, then $a b c=$

Logarithm

Solution:

(i) Equate the given ratios to $k$ and get the values of $\log a, \log b$, and $\log c$.
(ii) Add $\log a, \log b$, and $\log c$ and solve for $a b c$.