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Q.
If $L, R, C$ denote inductance, resistance and capacitance, respectively. Then dimensions of $\frac{L}{R^{2}C}$ are
Physical World, Units and Measurements
Solution:
$\frac{L}{R}=$ time constant of $L-R$ circuit $=\left[M^{0}L^{0}T\right]$
$RC =$ time constant of $R-C$ circuit $=\left[M^{0}L^{0}T\right]$
$\therefore $ The dimensions of
$\frac{L^{2}}{R^{2}C}=\left(\frac{L}{R}\right)\times\frac{1}{RC}$
$=\frac{\left[M^{0}L^{0}T\right]}{M^{0}L^{0}T}=\left[M^{0}L^{0}T^{0}\right]$