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  4. If KMnO4 is reduced by oxalic acid in an acidic medium, then oxidation number of Mn changes from

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Q. If $ KMnO_{4} $ is reduced by oxalic acid in an acidic medium, then oxidation number of $Mn$ changes from

Uttarkhand PMTUttarkhand PMT 2007

Solution:

$2\overset{+7}{KMnO _{4}}+3 H _{2} SO _{4} \rightarrow K _{2} SO _{4}+2 \overset{+2}{MnSO _{4}} $
$+3 H _{2} O +5[ O ] 5 H _{2} C _{2} O _{4}+5[ O ] \rightarrow 10 CO _{2}+5 H _{2} O$
Here, $Mn ^{+7}$ in $KMnO _{4}$
has been reduced to
$Mn ^{2+}$ in $ MnSO _{4}$.