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  4. If k times the sum of first n natural numbers is equal to the sum of the squares of the first n natural numbers, then cos -1((2 n-3 k/2)) is equal to

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Q. If $k$ times the sum of first $n$ natural numbers is equal to the sum of the squares of the first $n$ natural numbers, then $\cos ^{-1}\left(\frac{2 n-3 k}{2}\right)$ is equal to

Inverse Trigonometric Functions

Solution:

$2n - 3k = -1$