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Chemistry
If Ks p is the solubility products of a sparingly soluble salt A3 X2, then its solubility is :
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Q. If $K_{s p}$ is the solubility products of a sparingly soluble salt $A_{3} X_{2}$, then its solubility is :
Equilibrium
A
$\left(K_{s p} / 108\right)^{1 / 5}$
80%
B
$\left(K_{s p}\right)^{1 / 5}$
20%
C
$\left(K_{\text {sp }} / 72\right)^{1 / 5}$
0%
D
$\left(K_{s p}\right)^{1 / 2}$
0%
Solution:
$\underset {1-s}{A_3 X_2} \rightleftharpoons \underset {3s}{3A^{2+}} + \underset {2s}{2X^{3-}} $
$K_{\mathrm{sp}}=(3 s)^{3}(2 s)^{2}=108 s^{5}$
$s=\left(\frac{K_{s p}}{108}\right)^{1 / 5}$