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  4. If k ∈ R and the middle term of ((k/2)+2)8 is 1120 , then value of k is:

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Q. If $k \in R$ and the middle term of $\left(\frac{k}{2}+2\right)^8$ is $1120$ , then value of $k$ is:

Binomial Theorem

Solution:

middle term $= T _5$
$T_5=T_{4+1}={ }^8 C_4 \cdot k^4=1120$
$ \Rightarrow k=2$