1. Tardigrade
  2. Question
  3. Chemistry
  4. If Kc is the equilibrium constant for the formation of NH3 . The dissociation constant of ammonia under the same temperature will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $ K_{c} $ is the equilibrium constant for the formation of $ NH_{3} $ . The dissociation constant of ammonia under the same temperature will be

AMUAMU 2007

Solution:

$NH _{3} \rightleftharpoons \frac{1}{2} N _{2}+\frac{3}{2} H _{2} $
$ K_{c}=\frac{\left[ N _{2}\right]^{1 / 2}\left[ H _{2}\right]^{3 / 2}}{\left[ NH _{3}\right]}$ ...(i)
$\frac{1}{2} N _{2}+\frac{3}{2} H _{2} \rightleftharpoons NH _{3} $
$K_{c}'=\frac{\left[ NH _{3}\right]}{\left[ N _{2}\right]^{1 / 2}\left[ H _{2}\right]^{3 / 2}}$...(ii)
So, for dissociation $K'=\frac{1}{K_{c}}$