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  4. If in the lift, the body of mass 5 kg is suspended to spring balance, the lift moves downward with acceleration 10 text m/s2, then the reading of spring balance is

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Q. If in the lift, the body of mass $5\, kg$ is suspended to spring balance, the lift moves downward with acceleration $ 10\text{ }m/{{s}^{2}}, $ then the reading of spring balance is

Rajasthan PETRajasthan PET 2003

Solution:

$ F=m(g-a) $ $ =5(10-10)=0 $