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Q. If in the circuit, power dissipation is $150\, W$, then $R$ is :Physics Question Image

AIEEEAIEEE 2002Current Electricity

Solution:

$P=\frac{V^{2}}{R_{ ncl }}$
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$150=\frac{(15)^{2}}{\frac{R \cdot 2}{2+R}} \Rightarrow R=6 \Omega$