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Q. If $i ^{ i ^{-*}}= A + iB ( i = iota =\sqrt{-1})$ then

Complex Numbers and Quadratic Equations

Solution:

Correct answer is (a) $\tan \frac{\pi}{2} A =\frac{ B }{ A }$Correct answer is (c) $A^2+B^2=e^{-\pi B}$