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Q. If $i^2=-1$ and $(-i)^2=i^2=-1$, then $\sqrt{-1}$ is equal to

Complex Numbers and Quadratic Equations

Solution:

$(i)^2=-1$ and $(-i)^2-i^2=-1$
Therefore, square roots of $-1$ are $i,-i$. However, by the symbol $\sqrt{-1}$ we would mean (i) only.