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Physics
If half-life of radium is 77 days. Its decay constant in day will be
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Q. If half-life of radium is 77 days. Its decay constant in day will be
Rajasthan PET
Rajasthan PET 2010
A
$ 3\times {{10}^{-3}}/day $
B
$ 9\times {{10}^{-3}}/day $
C
$ 1\times {{10}^{-3}}/day $
D
$ 6\times {{10}^{-3}}/day $
Solution:
Decay constant, $ \lambda =\frac{0.693}{{{T}_{1/2}}}=\frac{0.693}{77} $
$ =9\times {{10}^{-3}}/day $