Question

If $H _{2} SO _{4}$ ionises as $H _{2} SO _{4}+2 H _{2} O \rightarrow 2 H _{3} O ^{+}+ SO _{4}^{2-}$ Then total number of ions produced by $0.1 \, mol\, H _{2} SO _{4}$ will be:

• A. $9.03 \times 10^{21}$
• B. $3.01 \times 10^{22}$
• C. $6.02 \times 10^{22}$
• D. $1.8 \times 10^{23}$

Answer 1

Answer: (D)

$1 \, M$ produces ions $=3$ moles

$\therefore 0.1 \, M \, H _{2} SO _{4}$ produce ions $=0.3\, mol$

Number of ions$=0.3 \times 6.02 \times 10^{23}$

$=1.8 \times 10^{23}$