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  4. If g(x)=1+√x and f(g(x))=3+2 √x+x, then f(x) is

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Q. If $g(x)=1+\sqrt{x}$ and $f(g(x))=3+2 \sqrt{x}+x$, then $f(x)$ is

Relations and Functions - Part 2

Solution:

$f (1+\sqrt{ x })=3+2 \sqrt{ x }+ x$
Put $1+\sqrt{x}=y \Rightarrow f(y)=2+y^2$.