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Q. If $g(x)=1-x^2$ and $f(g(x))=\frac{1-x^2}{x^2}$ when $x \neq 0$, then $f(1 / 2)$ equals

Relations and Functions - Part 2

Solution:

Since $g ( x )=1 / 2$ is satisfied by $x =\sqrt{1 / 2}$
$f (1 / 2)= f ( f (\sqrt{1 / 2}))=1$