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  4. If g is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is

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Q. If $g$ is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is

J & K CETJ & K CET 2008Gravitation

Solution:

Acceleration due to gravity at a height $h$ from the surface of the earth
$g'=g \frac{1}{\left(1+\frac{h}{R}\right)^{2}}$
Given $h=2 R$
$\therefore g'=g \frac{1}{(1+2)^{2}}$
or $g'=\frac{g}{9}$