Question

If force $(F)$, length $(L)$ and time $(T)$ are assumed to be the fundamental units, then the dimensional formula of the mass will be

• A. $ [FL^{-1}T^{2}]$
• B. $ [FL^{-1}T^{-2}]$
• C. $ [FL^{-1}T^{-1}]$
• D. $ [FL^{2}T^{2}]$

Answer 1

Answer: (A)

By Newton's second law
Force $(F)=$ mass (M) $\times$ acceleration
$\therefore $ Dimensions of $[F]=\left[M L T^{-2}\right]$
$\Rightarrow [M]=\left[F L^{-1} T^{2}\right]$