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Q.
If for $AX = B,B = \begin{bmatrix}9\\ 52\\ 0\end{bmatrix} $ and $A^{-1} = \begin{bmatrix}3& -1/2&-1/2\\ -4&3/4&5/4\\ 2&-3/4&-3/4\end{bmatrix}$ then X is equal to :
Determinants
Solution:
Here $X = A^{-1} B $
i.e., X = $\begin{bmatrix}3&-1/2&-1/2\\ -4&3/4&5/4\\ 2&-3/4&-3/4\end{bmatrix}_{3\times3} \begin{bmatrix}9\\ 52\\ 0\end{bmatrix}_{3\times1}$
$ = \begin{bmatrix}1\\ 3\\ -21\end{bmatrix}_{3\times1} $