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Q. If for a weak acid $HA ,\, K_{a} =10^{-5}$ then value of $pK _{ b }$ for $A_{(a q)}^{-}$ is

Solution:

For conjugate acid-base pair.
$pK _{ b }=14- pK _{ a } $
$\left[ pK _{ a }=-\log K _{ a }=-\log 10^{-5}=5\right]$
$=14-5=9$