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Physics
If for a gas, (R/CV)=0.67, this gas is made up of molecules which are
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Q. If for a gas, $\frac {R}{C_V}=0.67, $ this gas is made up of
molecules which are
AIPMT
AIPMT 1992
A
diatomic
14%
B
mixture of diatomic and polyatomic molecules
10%
C
monoatomic
67%
D
polyatomic
9%
Solution:
Since $\frac {R}{C_V}=0.67\, \Rightarrow \frac {C_P-C_V}{C_V}=0.67 $
$\Rightarrow \gamma =1.67= \frac {5}{3} $
Hence gas is monoatomic.