1. Tardigrade
  2. Question
  3. Mathematics
  4. If f( x , y )=( max ( x , y )) min ( x , y ) and g( x , y )= max ( x , y )- min ( x , y ), thenf(g(-1,-(3/2)), g(-4,-1.75)) equals

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Q. If $f( x , y )=(\max ( x , y ))^{\min ( x , y )}$ and $g( x , y )=\max ( x , y )-\min ( x , y )$, then$f\left(g\left(-1,-\frac{3}{2}\right), g(-4,-1.75)\right)$ equals

Relations and Functions - Part 2

Solution:

$g\left(-1,-\frac{3}{2}\right)=\max \left(-1,-\frac{3}{2}\right)-\min \left(-1,-\frac{3}{2}\right)=-1-\left(-\frac{3}{2}\right)=\frac{1}{2}$
and$g (-4,-1.75)=\max (-4,-1.75)-\min (-4,-1.75)=-1.75-(-4)=2.25=\frac{9}{4}$
Then
$\left. f \left(\frac{1}{2}, \frac{9}{4}\right)=\left(\max \left(\frac{1}{2}, \frac{9}{4}\right)\right)^{\min \left(\frac{1}{2}, \frac{9}{4}\right)}=\left(\frac{9}{4}\right)^{\frac{1}{2}}=\frac{3}{2}\right]$