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Q. If $f(x) = x \, \sin x$, then $f' \left(\frac{\pi}{2} \right)$ is equal to

Limits and Derivatives

Solution:

AS $f'(x) = x \, \cos x + \sin x$
So, $f' \left( \frac{\pi}{2}\right) = \frac{\pi}{2} \cos \frac{\pi}{2} +\sin \frac{\pi}{2} = 1$