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Q. If $f(x) = \begin{vmatrix}x^{3}-x&a+x&b+x\\ x-a&x^{2}-x&c+x\\ x-b&x-c&0\end{vmatrix}$ then

KCETKCET 2020

Solution:

$f(0) = \begin{vmatrix} 0& a& b\\ -a& 0&c \\-b & -c& 0\end{vmatrix}$
$f(0)$ is the determinant of skew-symmetric matrix of order $3$ (odd).
$∴f(0) = 0.$