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Q. If $f(x)=\frac{7^{1+\log x}}{x^{\log 7}}$ then $f(2021)=$

Solution:

$f(x)=\frac{7^{1+\log x}}{x^{\log 7}}$
$=\frac{7.7^{\log x}}{7^{\log x}}$
$=7$