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Mathematics
If f(x)=3 x4+4 x3-12 x2+12, then f ( x ) is
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Q. If $f(x)=3 x^{4}+4 x^{3}-12 x^{2}+12$, then $f ( x )$ is
BITSAT
BITSAT 2019
A
increasing in $(-\infty,-2)$ and in $(0,1)$
B
increasing in $(-2,0)$ and in $(1, \infty)$
C
decreasing in $(-2,0)$ and in $(0,1)$
D
decreasing in $(-\infty,-2)$ and in $(1, \infty)$
Solution:
$\because f(x)=3 x^{4}+4 x^{3}-12 x^{2}+12 f(x)=12 x^{3}+12 x^{2}-24 x$
$=12 x\left(x^{2}+x-2\right)$
$=12 x(x-1)(x+2)$
From above it is clear that $f(x)$ is increasing in $(-2,0)$ and in $(1, \infty)$