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Q. If $f(x) = 3x-1$ and $g(x) = 5x + 6$ then $(g^{-1} \: of^{-1}) (2)=$

Relations and Functions - Part 2

Solution:

$f^{-1}\left(x\right) =\frac{x+1}{3} $
$g^{-1}\left(x\right)=\frac{x-6}{5},g^{-1}of^{-1}\left(2\right)=g^{-1}\left(f^{-1}\left(2\right)\right)$