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  4. If f(x) = 2x - 1,g(x) = x2, then (3 f - 2g)(x) =

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Q. If $f(x) = 2x - 1,g(x) = x^2$, then $(3 f - 2g)(x) = $

Relations and Functions

Solution:

$(3f - 2g)(x) = 3f(x)- 2g(x)$