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  4. If f(x)=(1- tan x/4 x-π), x ≠ (π/4), x ∈[0, (π/2)) is a continuous functions, then f(π / 4) is equal to -

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Q. If $f(x)=\frac{1-\tan x}{4 x-\pi}, x \neq \frac{\pi}{4}, x \in\left[0, \frac{\pi}{2}\right)$ is a continuous functions, then $f(\pi / 4)$ is equal to -

Continuity and Differentiability

Solution:

Correct answer is (a) $-1 / 2$