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  4. If f: R arrow R be defined by f(x)= begincases2 x &: x>3 x2 &: 1 < x ≤ 3 3 x &: x ≤ 1 endcases then f(-1)+f(2)+f(4) is

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Q. If $f: R \rightarrow R$ be defined by
$f(x)=\begin{cases}2 x & : & x>3 \\x^{2} & : & 1 < x \leq 3 \\3 x & : & x \leq 1\end{cases}$
then $f(-1)+f(2)+f(4)$ is

KCETKCET 2022Relations and Functions

Solution:

$f(-1)=3(-1)=-3$
$f(2)=2^{2}=4$
$f(4)=2(4)=8$
$f(-1)+f(2)+f(4)$
$=-3+4+8=9$