Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If error in measuring diameter of a circle is $4 \%$, the percentage error in circumference of the circle would be

Physical World, Units and Measurements

Solution:

Circumference, $s=2 \pi r=2 \pi \frac{D}{2}=\pi D$
$\therefore \frac{\Delta s}{s} \times 100=\frac{\Delta D}{D} \times 100=4 \%$