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Q. If $ {\varepsilon}_0 $ and $ {\mu}_0 $ are the electric permittivity and magnetic permeability in a free space, $ \varepsilon $ and $\mu $ are the corresponding quantities in medium, the index and refraction of the medium is

AIPMTAIPMT 1997Electromagnetic Waves

Solution:

$c=\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}$ (free space)
$v=\frac{1}{\sqrt{\mu \varepsilon}}$ (medium)
$\therefore \mu=\frac{c}{v}=\sqrt{\frac{\mu \varepsilon}{\mu_{0} \varepsilon_{0}}}$