Question

If enthalpy of formation of $ICl _{(g)}, Cl _{(g)}$ and $I _{(g)}$ is $17.57 , 121.34$ and $106.96\, J\, mol^{-1}$ respectively. Then bond dissociation energy of $I - Cl$ bond is

• A. $35.15 \, J\, mol^{-1}$
• B. $106.69\, J\, mol^{-1}$
• C. $210.73\, J\, mol^{-1}$
• D. $420.9\, J\, mol^{-1}$

Answer 1

Answer: (C)

$\Delta H =\Delta H_{f( I )}^{\circ}+\Delta H_{f( Cl )}^{\circ}-\Delta H_{f( ICl )}^{\circ}$ $=106.96+121.34-17.57=210.73 \,J \,mol ^{-1}$