Thank you for reporting, we will resolve it shortly
Q.
If ends of latus rectum of parabola $(x+1)^2=4(y+1)$ are vertices of an ellipse whose eccentricity is half of eccentricity of parabola, then for ellipse,
Conic Sections
Solution:
Coordinate of foci $=(-1 \pm ae , 0)=(-2,0)$ and $(0,0)$
Equation of directrix $x=-1 \pm \frac{ a }{ e }$
$\Rightarrow( x +5)( x -3)=0$