Question

If electron, hydrogen, helium and neon nuclei are all moving with the velocity of light, then the wavelengths associated with these particles are in the order

• A. electron $>$ hydrogen $>$ helium $>$ neon
• B. electron $>$ helium $>$ hydrogen $>$ neon
• C. electron $<$ hydrogen $<$ helium $<$ neon
• D. neon $<$ hydrogen $<$ helium $<$ electron

Answer 1

Answer: (A)

$\lambda=\frac{h}{m v} ;$ when $v$ is same

$\lambda \propto \frac{1}{m}$

Thus, the order of wavelength is electron $ >$ hydrogen $ >$ helium $ >$ neon.